$T h e L C M o f (16 - x^{2}) a n d$ $(x^{2} + x - 6) i s$

(x - 3) (x + 3) (4 - x^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 (4 - x^{2}) (x + 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(4 - x^{2}) (x - 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D None of these
$16 - x^{2} = (4 - x) (4 + x) (x^{2} + x - 6) = (x + 3) (x - 2) L C M w i l l (16 - x^{2}) (x^{2} + x - 6)$

Suggest Corrections

Similar questions

(16 - x^{2})

(x^{2} + x - 6)

- x^{2} - x + 6, - x^{2} + x + 2

h (x)

h (x)

m (x)

16 - 4 x^{2}, x^{2} + x - 6

x^{2} - 4 a n d x^{2} - 5 x + 6

x^{2} - 5 x + 6, x^{2} + 4 x - 12

x - 2

Join BYJU'S Learning Program