Question

The LCM of two numbers is 12 times their HCF. The sum of HCF and LCM is 403. If one of the numbers is 93 then the other number is

• A. $124$
• B. $128$
• C. $134$
• D. $138$

Answer 1

The correct option is A $124$

Let the HCF $=x$

According to the question LCM$=12x$

$x+12x=403$

$13x=403\Rightarrow x=31$

$\therefore HCF=31andLCM=12\times 31=372$

Let the second number $=y$

$Productofnumbers=HCF\times LCM$

$93\times y=31\times 372$

$y=\frac{31\times 372}{93}$

$y=124$

Hence the second number is $124$