Question

The LCM of two numbers is 567 and their HCF is 9 If the difference between the two numbers is 18 find the two numbers

• A. 36 and 18
• B. 78 and 60
• C. 63 and 81
• D. 52 and 34

Answer 1

Answer: (C)

63 and 81

$Productoftwonumber=LCM\times HCF$
$\Rightarrow 567\times 9=5103$
Let the number are x and x+18
then$x(x+18)=5103$
$x^2+18x-5103=0$
$x^2+81x-63x-5103=0$
$x(x+81)-63(x+81)=0$
$(x+81)(x-63)=0$
The number are 63 and 81