The LCM of two numbers x and y is z. What is their HCF?

^yz/_x

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^xy/_z

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^xz/_y

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xyz

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Solution

The correct option is B
^xy/_z

We know that for two positive integers x and y, LCM (x,y) × HCF(x,y)=x × y

Hence the answer is

^xy/_z

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Similar questions

x + y + z = 6

(x y + y z + z x) = 11

x^{3} + y^{3} + z^{3} - 3 x y z

x^{3} + y^{3} + z^{3} - 3 x y z = (x + y + z) (x^{2} + y^{2} + z^{2} - x y - y z - z x)

If $x + y + z = 8$ and $x y + y z + z x = 20$ , find the value of $x^{3} + y^{3} + z^{3} - 3 x y z$ .

x + y + z = 6

x y + y z + z x = 12

x^{3} + y^{3} + z^{3} = 3 x y z

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