The LCM of two prime numbers x and y ( x > y ) is 161. The value of (3y-x) is :

- 2

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Solution

The correct option is A $- 2$
$161 = 7 \times 23$
So, $x = 23$ and $y = 7$
Therefore,
$(3 y - x) = (3 \times 7 - 23) = - 2$

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Similar questions

x

y

(x > y)

161

3 y - x

\frac{y}{x}

P^{x} \times Q^{y},

x = \frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}

y = 1

\frac{x - y}{x - 3 y}

Find the value of x and y.
$\frac{2}{x} + \frac{2}{3 y} = \frac{1}{6} \frac{3}{x} + \frac{4}{y} = \frac{- 1}{2}$

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