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B
v(v+1)(v−1)(v2+v+1)
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C
v(v+1)(v−1)
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D
v(v−1)(v2+v+1)
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Solution
The correct option is B
v(v+1)(v−1)(v2+v+1)
First expression, 'v2−v' can be written as 'v(v−1)'. Second expression, '(v−1)2' can be written as '(v−1)(v−1)'. Third expression = v3−1 = (v−1)(v2+v+1)