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Question

The LCM of (x−1)(x−2) and (x−2)(x−7) is:

A
(x1)(x2)
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B
(x1)(x2)(x7)
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C
(x2)(x7)
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D
(x1)(x7)
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Solution

The correct option is B (x1)(x2)(x7)
The irreducible factors occuring in (x1)(x2) and (x2)(x7) are (x1),(x2) and (x7)
The greatest exponents of these respectively are 1,1 and 1.
Hence, the LCM = (x1)1× (x2)1× (x7)1 = (x1)(x2)(x7).

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