CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The LCM of (x−1)(x−2) and (x−2)(x−7) is:

A
(x1)(x2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(x1)(x2)(x7)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(x2)(x7)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(x1)(x7)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (x1)(x2)(x7)
The irreducible factors occuring in (x1)(x2) and (x2)(x7) are (x1),(x2) and (x7)
The greatest exponents of these respectively are 1,1 and 1.
Hence, the LCM = (x1)1× (x2)1× (x7)1 = (x1)(x2)(x7).

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lowest Common Multiple
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon