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Monotonically Increasing Functions

The least and...

Question

The least and the greatest distance of the point (10, 7) for the circle $x^{2} + y^{2} - 4 x - 2 y - 20 =$ are

10, 5

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15, 20

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12, 16

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5, 15

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Solution

The correct option is D
5, 15

cp--r,cp+r

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Similar questions

(10, 7)

x^{2} + y^{2} - 4 x - 2 y - 20 = 0

(10, 7)

x^{2} + y^{2} - 4 x - 2 y - 20 = 0

(10, 7)

x^{2} + y^{2} - 4 x - 2 y - 20 = 0

P (10, 7)

x^{2} + y^{2} - 4 x - 2 y - 20 = 0

P (10, 7)

C : x^{2} + y^{2} - 4 x - 2 y - 20 = 0

l, m

C

{(9 l + 2 m)}^{2}

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