Question

The least count of a screw gauge can be practically decreased by _________________.

• A. increasing the total number of divisions on the main scale
• B. decreasing the total number of divisions on the circular scale
• C. increasing the total number of divisions on the circular scale
• D. constructing the gauge with an alloy of iron, tin, and lead

Answer 1

The correct option is C

increasing the total number of divisions on the circular scale

Least count of the screw gauge is given by the expression,
LC = (pitch of the screw)/ (number of circular scale divisions)

To reduce the LC we can increase the denominator, i.e the number of scale divisions.

Therefore the correct answer is option A.