Question

The least count of a stop watch is 0.2 second. The time of 20 oscillations of a pendulum is measured to be 25 second. The percentage error in the measurement of time will be :

• A. 8%
• B. 1.8%
• C. 0.8%
• D. 0.1%

Answer 1

Answer: (C)

0.8%

Percentage error $=\frac{\Delta t}{t}\times 100=\frac{0.2}{25}\times 100=0.8$