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Multiplication & Division of Errors

The least cou...

Question

The least count of a stop watch is 0.2 second.The time of 20 oscillations of a pendulum is measured to be 25 seconds.The percentage error in time period is

A

16%

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B

0.8%

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C

1.8%

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D

8%

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Solution

The correct option is D 0.8%
Percentage error= $\frac{l e a s t c o u n t}{m e a s u r e m e n t} \times 100$
$= \frac{0.2}{25} \times 100 = 0.8$ %

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