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Vernier Caliper

The least cou...

Question

The least count of a vernier caliper having $20$ vernier divisions when $1 M . S . D . = 0.1 c m$ is :

A

0.5 m m

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B

0.05 c m

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C

0.05 m m

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D

0.5 c m

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Solution

The correct option is C $0.05 m m$
One main scale division is given as $1 M . S . D = 0.1 c m$
Number of vernier divisions $N = 20$
So, least count $L . C = \frac{1 M . S . D}{N} = \frac{0.1}{20} c m = 0.005 c m$
$⟹ L . C = 0.05 m m$ $(∵ 1 c m = 10 m m)$

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