The least distance between two points on the equatorial circle on the surface of the earth having polar coordinates $(R, 0)$ and $(R, π / 2)$ with respect to the origin at the centre of the Earth is:

R

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R / 2

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R π / 2

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R π

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Solution

The correct option is C $R π / 2$
Two points on the equatorial circle are shown in the figure.
Least distance between them is equal to the $\frac{1}{4} t h$ of the circumference of the circle of radius $R$ .
Thus least distance $= \frac{2 π R}{4} = \frac{π R}{2}$

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The least distance between two points on the equatorial circle on the surface of the earth having polar coordinates (R,0) and (R,π/2) with respect to the origin at the centre of the Earth is:

The correct option is C Rπ/2Two points on the equatorial circle are shown in the figure.Least distance between them is equal to the 14th of the circumference of the circle of radius R.Thus least distance =2πR4=πR2

The least distance between two points on the equatorial circle on the surface of the earth having polar coordinates $(R, 0)$ and $(R, π / 2)$ with respect to the origin at the centre of the Earth is:

The correct option is C $R π / 2$
Two points on the equatorial circle are shown in the figure.
Least distance between them is equal to the $\frac{1}{4} t h$ of the circumference of the circle of radius $R$ .
Thus least distance $= \frac{2 π R}{4} = \frac{π R}{2}$