The least distance from origin to the circle $(x - 6)^{2} + (y - 8)^{2} = 9^{2}$ is

\sqrt{3}

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\sqrt{2}

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2

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1

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Solution

The correct option is C $1$
Given equation of circle is
$(x - 6)^{2} + (y - 8)^{2} = 9^{2}$
Center is $(6, 8)$ and radius $r = 9$
Shortest distance from point $(x_{1}, y_{1})$ to circle is
$d = | \sqrt{{(x_{1} - h)}^{2} + {(y_{1} - k)}^{2}} - r |$
So, here , $d = | 10 - 9 | = 1$

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