The correct option is B 2√5 units
For given circle, centre will be (−32,14) and radius r=√5 units
Now, perpendicular distance from centre to the line 8x−4y+73=0 is
d=∣∣
∣
∣
∣∣8(−32)−4(14)+73√82+(−4)2∣∣
∣
∣
∣∣
⇒d=∣∣∣604√5∣∣∣=3√5>r units
So, line lies externally to the circle.
∴ least distance is |d−r|=2√5 units