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Question

The least integral value of k such that (k2)x2+8x+k+4 is positive for all real values of x is

A
1
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B
2
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C
3
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D
5
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Solution

The correct option is D 5
(k2)x2+8x+(k+4)>0 xR
D=644(k2)(k+4)<0 and k2>0
(k+6)(k4)>0 k>2
k<6 or k>4
k>4
k=5

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