The least integral value of x which satisfies -3x-7-3- is

For √(3x 7) gt;3 to be defined 3x 7≥ 0⇒ x≥73 nbsp; Now squaring both sides, nbsp; 3x 7 gt;9 ⇒ 3x gt;16 ⇒ x gt;163 On taking intersection of both t ...

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Standard XI

Mathematics

Method of Intervals

The least int...

Question

The least integral value of $x$ which satisfies $\sqrt{3 x - 7} > 3$ , is

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Solution

For $\sqrt{3 x - 7} > 3$ to be defined
$3 x - 7 \geq 0 \Rightarrow x \geq \frac{7}{3}$

Now squaring both sides,
$3 x - 7 > 9 \Rightarrow 3 x > 16 \Rightarrow x > \frac{16}{3}$

On taking intersection of both the conditions, we get
$x > \frac{16}{3}$
or $x > 5 + \frac{1}{3}$
Hence least ingeral value of $x$ is $6$

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The least integral value of x which satisfies √3x−7>3, is

For √3x−7>3 to be defined 3x−7≥0⇒x≥73 Now squaring both sides, 3x−7>9⇒3x>16⇒x>163 On taking intersection of both the conditions, we get x>163 or x>5+13 Hence least ingeral value of x is 6

The least integral value of $x$ which satisfies $\sqrt{3 x - 7} > 3$ , is