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Byju's Answer
Standard XI
Mathematics
Points of Discontinuity
The least int...
Question
The least integral value of
x
, which satisfy the inequality
x
2
−
3
x
+
4
x
2
−
6
x
+
8
≤
0
is
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Solution
x
2
−
3
x
+
4
x
2
−
6
x
+
8
≤
0
⇒
x
2
−
3
x
+
4
(
x
−
4
)
(
x
−
2
)
≤
0
We know that,
x
2
−
3
x
+
4
>
0
∵
D
=
9
−
12
<
0
The critical points are
2
,
4
∴
x
∈
(
2
,
4
)
Hence, the least integral value of
x
is
3
.
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