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Question

The least integral value of x, which satisfy the inequality x23x+4x26x+80 is

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Solution

x23x+4x26x+80
x23x+4(x4)(x2)0

We know that,
x23x+4>0 D=912<0
The critical points are 2,4
x(2,4)

Hence, the least integral value of x is 3.

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