The least intercept made by the cordinate axes on a tangent to the ellipse $\frac{x^{2}}{64} + \frac{y^{2}}{49} = 1$ is:

40

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30

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15

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100

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Solution

The correct option is C $15$
Least intercept by coordinates axes on tangent to ellipse $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ is (a+b).
So, for the ellipse $\frac{x^{2}}{64} + \frac{y^{2}}{49} = 1$ , least intercept is $8 + 7 = 15$

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