Question

The least multiple of $7$, which leaves the remainder $4$, when divided by any of $6,9,15$ and $18$ is

• A. $76$
• B. $94$
• C. $184$
• D. $364$

Answer 1

The correct option is D $364$

LCM of $6,9,15$and $18=90$
$\therefore$ Required number $=90k+4$, which must be a multiple of $7$ for some value of $k$.
By hit and trial, we can get for $k=4$
Number $=90\times 4+4=364$, which is exactly divisible by $7$.