The least number which gives a remainder of 2, 3 and 4 when successively divided by 3,x and 8 respectively is 71. Find x.
4
6
5
7
Solving, we get (4x + 3)×3+2 = 71 ⟹ x=5.
Find the least number which when divided by 9,10 and 11 give remainders of 2,3 and 5 respectively?