The least number which on division by 35 leaves a remainder 25 and on division by 45 leaves the remainder 35 and on division by 55 leaves the remainder of 45 is
A
2515
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B
3455
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C
2875
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D
2785
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Solution
The correct option is B 3455 35=5×7 45=3×3×5 55=5×11 LCM of (35,45,55)=3×3×5××7×11=3465 Since difference between divisor and remainder is 10 Hence least number is 3465−10=3455