Question

The least number which when divided by $12,15,20$ and $54$ leaves in each case a remainder of $8$ is

• A. $458$
• B. $548$
• C. $854$
• D. $584$

Answer 1

The correct option is B $548$

Explanation :

Required number

=$(L.C.M.of12,15,20,54)+8$

$12=2\times 2\times 3$

$15=3\times 5$

$20=2\times 2\times 5$

$54=2\times 3\times 3\times 3$

L.C.M. $=2\times 2\times 3\times 3\times 3\times 5=540$

Required number

=$540+8$

=$548$