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Question
The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
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Solution
The correct option is A 1683
LCM of 5, 6, 7 and 8 is 840. So, our number is of the form 840k + 3. The lowest value of K for which 840k + 3 is divisible by 9 is k = 2.
1683
LCM of 5, 6, 7 and 8 is 840. So, our number is of the form 840k + 3. The lowest value of K for which 840k + 3 is divisible by 9 is k = 2.
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