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Question

The least positive integer value of a for which both roots of the quadratic equation (a26a+5)x2+(a2+2a)x+(6aa28)=0 lie on either side of origin, is -

A
1
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B
2
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C
3
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D
6
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Solution

The correct option is C 3
a2+2a0a (,2][0,)
Since, both the roots lie on either side of the origin.
Product of roots < 0
CA<0
6aa28a26a+5<0
(a2)(a4)(a1)(a5)>0
So a (,2][0,1)(2,4)(5,)
So the least positive integer value of
a=3

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