The least positive of the function sin x-2-1-0 lies in the interval-

The correct option is A [0,π2] ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Period of Trigonometric Ratios

The least pos...

Question

The least positive of the function $(sin x - \frac{π}{2} + 1 = 0)$ lies in the interval,

[0, \frac{π}{2}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[\frac{π}{2}, π]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\frac{π}{2}, \frac{3 π}{2}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N o n e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

sin x - \frac{π}{2} + 1 = 0

{sin}^{5} x - {cos}^{5} x = \frac{1}{cos x} - \frac{1}{sin x}

sin x \neq cos x)

tan x > cot x

x \in (0, π) - {\frac{π}{2}}

{x \in R : | cos x | \geq sin x} \cap [0, \frac{3 π}{2}] =

(2 cos θ, 2 sin θ)

θ \in (0, 2 π)

x + y = 2

x - y = 2

θ

Join BYJU'S Learning Program