The least positive value of x such that 126 -x-4 6 isA- 2B- 4C- 6D- 8

The correct option is A 2126 ≡ nbsp;(x + 4)(mod 6) 126 (x + 4) = 6n, for some integer n. 122 x nbsp; = 6n 122 x is a multiple of 6. ∴The least posit ...

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Standard X

Mathematics

Modular Arithmetic and Congruence Modulo

The least pos...

Question

The least positive value of $x$ such that $126 \equiv (x + 4) (m o d 6)$ is _________.

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Solution

The correct option is A 2
$126 \equiv (x + 4) (m o d 6)$
$126 - (x + 4) = 6 n, for some integer n$ .
$122 - x = 6 n$
$122 - x$ is a multiple of 6.
$∴$ The least positive value of $x$ must be 2 as 122 - 2 = 120, which is the nearest multiple of 6 less than 122.

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The least positive value of x such that 126≡(x+4)(mod 6) is _________.

The correct option is A 2126≡(x+4)(mod 6) 126−(x+4)=6n,for some integer n. 122−x=6n 122−x is a multiple of 6. ∴The least positive value of x must be 2 as 122 - 2 = 120, which is the nearest multiple of 6 less than 122.

The least positive value of $x$ such that $126 \equiv (x + 4) (m o d 6)$ is _________.

The correct option is A 2
$126 \equiv (x + 4) (m o d 6)$
$126 - (x + 4) = 6 n, for some integer n$ .
$122 - x = 6 n$
$122 - x$ is a multiple of 6.
$∴$ The least positive value of $x$ must be 2 as 122 - 2 = 120, which is the nearest multiple of 6 less than 122.