The correct option is A 4
98≡(x+4)(mod 5)
⇒98−(x+4)=5n, for some integer n.
⇒94−x=5n
i.e., 94−x is a multiple of 5.
∴The least positive value of x so that 98≡(x+4)(mod 5) holds must be 4 as 94 - 4 = 90, which is the nearest multiple of 5 less than 94.