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The least pow...

Question

The least powerful oxidant in presence of $H_{2} O$ is:

F_{2}

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{C l}_{2}

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B r_{2}

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I_{2}

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Solution

The correct option is D $I_{2}$
The reactivity of halogens with water decreases from fluorine to iodine.
The least powerful oxidant in presence of water is iodine $I_{2}$ .
The net energy (a measure of the oxidation potential) of fluorine, chlorine, bromine and iodine is $- 186.6, - 147.5, - 136.5$ and $- 122.6$ kcal respectively.

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Similar questions

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

H_{2} O

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

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