The least stable hydride of 15th group elements is

N H_{3}

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P H_{3}

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A s H_{3}

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B i H_{3}

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Solution

The correct option is C $B i H_{3}$
$N H_{3}$ is the most stable hydride among the hydrides of group 15 elements because the strength of L-H (Here L = N, P, As, Sb, or Bi) bond decreases down the group due to increase in size of the central atom.

So, the decreasing order is:
$N H_{3} > P H_{3} > A s H_{3} > B i H_{3}$

So, the correct option is D.

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Similar questions

15

P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}

H

N H_{3}

S b

N H_{3}, P H_{3}, A S H_{3}, S b H_{3}, B i H_{3}

The increasing order of enthalpy of vaporization of NH₃, PH₃, and AsH₃ is

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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