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B
3
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C
4
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D
none of these
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Solution
The correct option is C 4 2log100a−loga10−4=2log10alog10100+4log1010log10a =2log10a2+41log10a For the two positive numbers log10a and 4log10a,AM≥GM ⇒log10a+4log10a2≥√log10a.4log10a=2 ∴log10a+4log10a≥4 Hence, option C is correct