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Question

The least value of 2sin2θ+3cos2θ is


A

1

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B

2

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C

3

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D

5

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Solution

The correct option is B

2


Solve the given expression

Given expression, 2sin2θ+3cos2θ

=2(1-cos2θ)+3cos2θ [sin2θ+cos2θ=1]

=2-2cos2θ+3cos2θ=2+cos2θ

Now, the minimum value will be obtained, when the value of cos2θ=0

Therefore, the least value of2sin2θ+3cos2θ=2 , so, option (B) is the correct answer.


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