The least value of 2sin2θ+3cos2θ is
1
2
3
5
Solve the given expression
Given expression, 2sin2θ+3cos2θ
=2(1-cos2θ)+3cos2θ [∵sin2θ+cos2θ=1]
=2-2cos2θ+3cos2θ=2+cos2θ
Now, the minimum value will be obtained, when the value of cos2θ=0
Therefore, the least value of2sin2θ+3cos2θ=2 , so, option (B) is the correct answer.