Question

The least value of ${(x^2-3)}^3+28$ is-

• A. $2^{27}$
• B. $2$
• C. $1$
• D. None of these

Answer 1

The correct option is C $1$

The value of $(x^2-3{)}^3+28$ will be least when $(x^2-3{)}^3$ is minimum .

$\to (x^2-3{)}^3$ will be minimum when $(x^2-3)$ is minimum .

$\to$ Minimum value of $(x^2-3)$ is $(-3)$ as $x^2$ is always positive .

$\to$ Thus minimum value of $(x^2-3{)}^3+28\to (-3{)}^3+28=1$