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Question

The least value of |z34i|2+|z+27i|2+|z5+2i|2 occurs when z=x+iy then the value of x is

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Solution

z=x+iy
|z34i|2+|z+27i|2+|z5+2i|2
=3(x2+y24x6y)+107
=3{(x2)2+(y3)2}+68
So, least value when x=2 and y=3
z=2+3i

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