The least value of |z−3−4i|2+|z+2−7i|2+|z−5+2i|2 occurs when z=x+iy then the real part of z is
A
2
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B
3
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C
√13
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D
None of these
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Solution
The correct option is A2 Let z=x+iy then |z−3−4i|2+|z+2−7i|2+|z−5+2i|2=|(x−3)+(y−4)i|2+|(x+2)+(y−7)i|2+|(x−5)+(y+2)i|2=3(x2+y2−4x−6y)+107=3[(x−2)2+(y−3)2]+68 This will have least value if x=2&y=3 So, real part of z=2