Question

The $\left[{Ag}^{+}\right]$ in a saturated solution of ${Ag}_{2}Cr{O}_4$ is $1.5\times {10}^{-4}M$. What is the solubility product of $A{g}_{2}Cr{O}_4$?

• A. $3.375\times {10}^{-12}$
• B. $1.6875\times {10}^{-10}$
• C. $1.6875\times {10}^{-11}$
• D. $1.6875\times {10}^{-12}$

Answer 1

The correct option is D $1.6875\times {10}^{-12}$

$A{g}_{2}Cr{O}_4\rightleftharpoons 2A{g}^{+}+Cr{O}_4^{2-}$

$\left[Cr{O}_4^{2-}\right]=\frac{1}{2}\times \left[A{g}^{+}\right]$

$K_{sp}=\left[A{g}^{+}{]}^2\right[Cr{O}_4^{2-}]=[1.5\times {10}^{-4}{]}^2[0.75\times {10}^{-4}]=1.6875\times {10}^{-12}$