The length a a rectangle is 15 cm more than its width . The perimeter is 150 cm . Find the measures of length and width of the rectangle

45,30

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40, 25

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50, 35

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45, 25

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Solution

The correct option is A 45,30
Let the breadth $= x$
the length $= x + 15$
given perimeter $= 150$
we know
Perimeter of rectangle $= 2 (l + b)$
150 = 2( x+ x+15)
$75 = 2 x + 15$
$60 = 2 x$
$30 = x$
therefore breadth $= 30$ cm
length $= 30 + 15 = 45$ cm
check
$150 = 2 (45 + 30)$
$150 = 2 (75)$
$150 = 150$
$L H S = R H S$
hence proved.

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The length of a rectangle is 5cm less than twice its width. If the length is decreased by 5cm and its width is increased by 2cm, the perimeter of the resulting rectangle will be 74 cm. Find the length of the original rectangle.

A rectangle's length is 5 cm less than twice its width. If the length is decreased by 5 cm and width is increased by 2 cm; the perimeter of the resulting will be 74 cm. Find the length and width of the original rectangle.

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The length a a rectangle is 15 cm more than its width . The perimeter is 150 cm . Find the measures of length and width of the rectangle

The correct option is A 45,30Let the breadth=x the length =x+15given perimeter=150we know Perimeter of rectangle=2(l+b)150 = 2( x+ x+15) 75=2x+15 60=2x30=xtherefore breadth =30 cm length =30+15=45 cmcheck 150=2(45+30)150=2(75)150=150 LHS=RHShence proved.