The length and breadth of a rectangle are 8 cm and 6 cm respectively. If its length is doubled and breadth is halved, then the new area is _____________cm²

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Solution

Length of the rectangle = $8 c m$
Breadth of the rectangle = $6 c m$
If length is doubled then new length = $2 \times 8 = 16 c m$
Breadth is halved, then new breadth = $\frac{6}{2} = 3 c m$
Hence, new area = $16 \times 3 = 48 c m$

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