The length and breadth of a rectangle is increased by $50 %$ and $25 %$ respectively; calculate the increase in area in percent.

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Solution

Percent increase in area
$[(1 + \frac{50}{100}) (1 + \frac{25}{100}) - 1] \times 100$
$= [\frac{3}{2} \times \frac{5}{4} - 1] \times 100$
$= [\frac{15}{8} - 1] \times 100$
$= \frac{7}{8} \times 100$
$= \frac{700}{8} = 87.5$ %

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The length and breadth of a rectangle is increased by 50% and 25% respectively; calculate the increase in area in percent.

Percent increase in area[(1+50100)(1+25100)−1]×100=[32×54−1]×100=[158−1]×100=78×100=7008=87.5%

The length and breadth of a rectangle is increased by $50 %$ and $25 %$ respectively; calculate the increase in area in percent.

Percent increase in area
$[(1 + \frac{50}{100}) (1 + \frac{25}{100}) - 1] \times 100$
$= [\frac{3}{2} \times \frac{5}{4} - 1] \times 100$
$= [\frac{15}{8} - 1] \times 100$
$= \frac{7}{8} \times 100$
$= \frac{700}{8} = 87.5$ %