Question

The length and breadth of a room are $16.58m$ and $8.32m$ respectively. The floor of the room is to be paved with square tiles of uniform size. Find the maximum number of tiles which may cover the floor entirely.

• A. $344560$
• B. $344864$
• C. $350000$
• D. $354000$

Answer 1

The correct option is B $344864$

Side of one tile

$=$ H.C.F of $16.58m$ and $8.32m$

$=$ H.C.F of $1658cm$ and $832cm$

$=2cm$

$\therefore$

No of tiles $=\frac{Areaofroom}{Areaofonesquaretile}$

$=\frac{1658\times 832}{2\times 2}$

$=344864$