Question

The length and breadth of a room are 3x²y³ and 6x³y², respectively. Find its perimeter and area.

Answer 1

$$\begin{gathered} \mathrm{We}\mathrm{have}, \\ \mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{room}=3x^2{y}^3\mathrm{and} \\ \mathrm{Breadth}\mathrm{of}\mathrm{the}\mathrm{room}=6x^3{y}^2 \\ \mathrm{Now},\mathrm{the}\mathrm{perimeter}\mathrm{of}\mathrm{the}\mathrm{room}=2\times \left(\mathrm{Length}+\mathrm{Breadth}\right) \\ =2\times \left(3x^2{y}^3+6x^3{y}^2\right) \\ =2\left(3x^2{y}^3+6x^3{y}^2\right) \\ \mathrm{Also},\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{room}=\mathrm{Length}\times \mathrm{Breadth} \\ =3x^2{y}^3\times 6x^3{y}^2 \\ =\left(3\times 6\right)\times \left(x^2\times x^3\right)\times \left(y^3\times y^2\right) \\ =18x^5{y}^5 \end{gathered}$$