The length and breadth of the rectangle park are in the ratio 5 : 4 and its area is 2880 m2, find the cost of fencing the park at the rate of Rs. 5 per metre.
Let the length and breadth of the rectangle as per the given ratio be 5x and 4x.
We know, area of rectangle = length x breadth
So, the area of the rectangular park
= 5x x 4x = 20 x2
According to the question,
Area of the rectangular park is 28802.
So, 20 x2 = 2880
⇒ x2 = 144
⇒ x = 12
So, 5x = 5 × 12 = 60
4x = 4 × 12 = 48
So, the perimeter of the park
= 2 (length + breadth)
= 2 (60 + 48)
= 2 × 108
= 216 cm
For 1 m, the cost of fencing = Rs. 5
For 216 m, the cost of fencing
= Rs. 5 x 216
= Rs. 1080