Question

The length and breadth of three rectangles are as given below: $\left(a\right)9mand6m\left(b\right)17mand3m\left(c\right)4mand14m$ . Which one has the largest area and which one has the smallest?

Answer 1

Step 1: Calculate area of rectangle with dimensions $9mand6m$

Here, Length$=9m$ and Breadth $=6m$

As, Area of rectangle $=lengthxbreadth$

$=9\times 6$

$=54m^2$

Step 2: Calculate area of rectangle with dimensions $17mand3m$

Here, Length =$17m$ and Breadth $=3m$

So, Area of rectangle $=17\times 3$

$=51m^2$

Step 3: Calculate area of rectangle with dimensions $4mand14m$

Here, Length$=4m$ and Breadth $=14m$

Area of rectangle$=4\times 14$

$=56m^2$

Since, $51<54<56$

Hence, Area of rectangle ( c ) is the largest area and (b) is the smallest.