Question

The length and breadth of three rectangles are given below. Find which on has greater perimeter and which one has least area.
(a) $10$ m and $6$ m
(b) $20$ m and $10$ m
(c) $15$ m and $5$ m

Answer 1

a) $10m$ & $6m$

Perimeter $=2(10+6)=32m$ & area $=10\times 6=60m^2$.

b) $20m$ & $10m$

Perimeter $=2(20+10)=60m$ & area $=20\times 10=200m^2$.

c) $15m$ & $5m$

Perimeter $=2(15+5)=40m$ & area $=15\times 5=75m^2$.

$\therefore$ the Rectangle which is having greatest perimeter is of perimeter $=60m$ i.e. option (b) and least area $=60m^2$, i.e. option(a).