Question

The length and the breadth of three rectangles are as follows:

(a) $9\text{m}$ and $6\text{m}$

(b) $17\text{m}$ and $3\text{m}$

(c) $4\text{m}$ and $14\text{m}$

Which one has the largest area and which one has the smallest?

Answer 1

Step 1: Find the area of first rectangle

The area $A$ of the rectangle with length $l$ and width $w$ is given by, $A=l\times w$.

According to the question

Substituting $9$ for $l$ and $6$ for $w$ into $A=l\times w$, we get

$\begin{array}{rcl}Are{a}_1& =& 9\times 6\\ & =& 54{\text{m}}^2\end{array}$

Step 2: Find the area of second rectangle

The area $A$ of the rectangle with length $l$ and width $w$ is given by, $A=l\times w$.

According to the question

Substituting $17$ for $l$ and $3$ for $w$ into $A=l\times w$, we get

$\begin{array}{rcl}Are{a}_2& =& 17\times 3\\ & =& 51{\text{m}}^2\end{array}$

Step 3: Find the area of third rectangle

The area $A$ of the rectangle with length $l$ and width $w$ is given by, $A=l\times w$.

According to the question

Substituting $4$ for $l$ and $14$ for $w$ into $A=l\times w$, we get

$\begin{array}{rcl}Are{a}_3& =& 4\times 14\\ & =& 56{\text{m}}^2\end{array}$

Hence, the rectangle having length and breadth $4\text{m}$ and $14\text{m}$ has the largest area whereas the rectangle having length and breadth $17\text{m}$ and $3\text{m}$ has the smallest area.