The length, breadth and height of a room are 6m, 4.5m and 3m respectively, find the cost of white washing the walls of the room and the ceiling at the rate of $R s . 8$ per $m^{2}$

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Solution

Area to be whitewashed $=$ area of four walls $+$ area of ceiling
Formulas to be noted $: -$
Area of four walls $= 2$ $($ length $+$ breadth $)$ $\times$ height
Area of ceiling $=$ area of rectangle = length $\times$ breadth
In the question, length of the room $= 6 m$
breadth of the room $= 4.5 m$
height of the room $= 3 m$
On the basis of formulas given above $: -$
Area of four walls $= 2 (6 m + 4.5 m) x 3 m$
Area of four walls $= 2 (10.5 m) x 3 m$
Area of four walls $= 21 m x 3 m$
Area of four walls $= 63 m^{2}$
Area of ceiling $= 6 m \times 4.5 m$
Area of ceiling $= 27 m^{2}$
Therefore, area to be whitewashed $= 63 m^{2} + 27 m^{2}$
Area to be whitewashed $= 90 m^{2}$
Cost of whitewashing $=$ rate at which area is being whitewashed $\times$ area to be whitewashed
Cost of whitewashing $= R s 8 / m^{2} \times 90 m^{2}$
Cost of whitewashing $= R s 8 \times 90$
Cost of whitewashing $= R s . 720.$

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The length, breadth and height of a room are 6m, 4.5m and 3m respectively, find the cost of white washing the walls of the room and the ceiling at the rate of Rs.8 per m2

The length, breadth and height of a room are 6m, 4.5m and 3m respectively, find the cost of white washing the walls of the room and the ceiling at the rate of $R s . 8$ per $m^{2}$