The length, breadth and height of a room are 90 m, 50 m and 40 m, respectively. Determine the longest tape which can measure the three dimensions of the room.
Given,
Length of the room = 90 m
Breadth of the room = 50 m
Height of the room = 40 m
To determine the longest tape which can measure all three dimensions, we need to calculate the HCF of 90, 50 and 40.
Prime factors are:
90 = 2 x 3 x 3 x 5
50 = 2 x 5 x 5
40 = 2 x 2 x 2 x 5
So, the H.C.F of 90, 50, 40 = 2 x 5 = 10
Hence, the answer is 10 metres.