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Question

The length, breadth and height of a room are 90 m, 50 m and 40 m, respectively. Determine the longest tape which can measure the three dimensions of the room.

A
45
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B
80
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C
15
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D
10
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Solution

The correct option is D 10

Given,

Length of the room = 90 m

Breadth of the room = 50 m

Height of the room = 40 m

To determine the longest tape which can measure all three dimensions, we need to calculate the HCF of 90, 50 and 40.

Prime factors are:

90 = 2 x 3 x 3 x 5

50 = 2 x 5 x 5

40 = 2 x 2 x 2 x 5

So, the H.C.F of 90, 50, 40 = 2 x 5 = 10

Hence, the answer is 10 metres.


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