The length, breadth and height of room are 825 cm, 675 cm and 650 cm respectively, find the longest tape which can increase the three dimensions of the room exactly.

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Solution

Length = $825 c m$ = $3 \times 5 \times 5 \times 11$
Breadth $= 675 c m$ = $3 \times 3 \times 3 \times 5 \times 5$
height = $450 c m = 2 \times 3 \times 3 \times 5 \times 5$
Longest tape = HCF of $825, 675$ and $450 = 3 \times 5 \times 5 = 75 c m$
Therefore , the longest tape is $75 c m$

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The length, breadth and height of room are 825 cm, 675 cm and 650 cm respectively, find the longest tape which can increase the three dimensions of the room exactly.

Length = 825cm = 3×5×5×11Breadth =675cm = 3×3×3×5×5height = 450cm=2×3×3×5×5Longest tape = HCF of 825,675 and 450=3×5×5=75cmTherefore , the longest tape is 75cm

Length = $825 c m$ = $3 \times 5 \times 5 \times 11$
Breadth $= 675 c m$ = $3 \times 3 \times 3 \times 5 \times 5$
height = $450 c m = 2 \times 3 \times 3 \times 5 \times 5$
Longest tape = HCF of $825, 675$ and $450 = 3 \times 5 \times 5 = 75 c m$
Therefore , the longest tape is $75 c m$